Solving 2x + 3y = 13 And 5x - 3y = 1 A Comprehensive Guide

Hey guys! Today, we're diving deep into the fascinating world of systems of equations. Specifically, we're going to break down a classic problem: solving the system of equations 2x + 3y = 13 and 5x - 3y = 1. This isn't just about finding the values of 'x' and 'y'; it's about understanding the methods, the logic, and the why behind each step. So, buckle up, grab your thinking caps, and let's get started!

Understanding Systems of Equations

First things first, what exactly is a system of equations? Simply put, it's a set of two or more equations that involve the same variables. Our goal? To find the values for those variables that satisfy all the equations in the system simultaneously. Think of it like a puzzle where each equation is a piece, and the solution is when all the pieces fit perfectly together. In our case, we have two equations and two variables (x and y), which makes it a solvable system, meaning we can find unique values for x and y that make both equations true.

Why are systems of equations important? Well, they pop up everywhere in real-world applications. From balancing chemical equations in chemistry to modeling supply and demand in economics, systems of equations are the workhorses behind countless calculations. They help us represent and solve problems involving multiple unknowns, making them an indispensable tool in various fields.

In tackling these systems, we often use a combination of algebraic techniques, graphical representations, and logical deduction. The journey to the solution is as valuable as the answer itself, as it hones our problem-solving skills and deepens our understanding of mathematical relationships. So, as we delve into the specifics of our example, remember that we're not just looking for numbers; we're exploring the art of mathematical thinking.

Method 1: The Elimination Method – A Step-by-Step Guide

One of the most efficient and widely used methods for solving systems of equations is the elimination method. The core idea behind this method is to manipulate the equations in such a way that when you add them together, one of the variables gets eliminated, leaving you with a single equation in a single variable. This makes it much easier to solve for the remaining variable. Then, you can substitute the value you found back into one of the original equations to find the value of the other variable. Let's see how this works in practice with our equations:

Step 1: Observe the Equations

Our system is:

  • 2x + 3y = 13
  • 5x - 3y = 1

Notice anything special? Look closely at the 'y' terms. We have a '+3y' in the first equation and a '-3y' in the second equation. This is a perfect setup for elimination! The coefficients of 'y' are already opposites, meaning that if we add the equations together, the 'y' terms will cancel out.

Step 2: Add the Equations

This is the heart of the elimination method. We add the left-hand sides of the equations together and set it equal to the sum of the right-hand sides:

(2x + 3y) + (5x - 3y) = 13 + 1

Now, let's simplify. Combine the 'x' terms and the 'y' terms:

2x + 5x + 3y - 3y = 14

7x = 14

See how the 'y' terms vanished? That's the magic of elimination!

Step 3: Solve for 'x'

We now have a simple equation with only one variable. To solve for 'x', we just need to divide both sides of the equation by 7:

7x / 7 = 14 / 7

x = 2

Fantastic! We've found the value of 'x'.

Step 4: Substitute 'x' and Solve for 'y'

Now that we know x = 2, we can substitute this value into either of the original equations to solve for 'y'. Let's use the first equation, 2x + 3y = 13, but we could just as easily use the second equation. The choice is yours!

2(2) + 3y = 13

4 + 3y = 13

Subtract 4 from both sides:

3y = 9

Divide both sides by 3:

y = 3

Step 5: The Solution

We've done it! We've found the values of both 'x' and 'y' that satisfy the system of equations. Our solution is:

  • x = 2
  • y = 3

We often write this as an ordered pair: (2, 3). This represents the point where the two lines represented by our equations intersect on a graph. More on that later!

In summary, the elimination method works by strategically adding or subtracting equations to eliminate one variable, making it possible to solve for the other. It's a powerful technique that's particularly useful when the coefficients of one of the variables are the same or opposites.

Method 2: The Substitution Method – Another Powerful Tool

Alright, guys, let's explore another fantastic method for tackling systems of equations: the substitution method. This technique is all about isolating one variable in one of the equations and then substituting that expression into the other equation. This, again, gives us a single equation with a single variable, which we can easily solve. It's like a clever algebraic dance – let's see how it's done!

Step 1: Choose an Equation and Isolate a Variable

The first step is to pick one of the equations and isolate one of the variables. This means getting the variable all by itself on one side of the equation. Which equation and which variable should you choose? A good strategy is to look for a variable that has a coefficient of 1 or -1, as this will make the isolation process simpler. In our system:

  • 2x + 3y = 13
  • 5x - 3y = 1

Neither variable has a coefficient of 1 or -1. In this case, we can choose any variable and any equation. Let's choose the second equation (5x - 3y = 1) and solve for x.

Add 3y to both sides:

5x = 1 + 3y

Divide both sides by 5:

x = (1 + 3y) / 5

Okay, we've successfully isolated 'x'. This expression, (1 + 3y) / 5, now represents the value of 'x' in terms of 'y'.

Step 2: Substitute

This is where the magic happens. We're going to take the expression we just found for 'x' and substitute it into the other equation – the one we didn't use in the previous step. In this case, that's the first equation, 2x + 3y = 13.

Replace 'x' with '(1 + 3y) / 5':

2 * ((1 + 3y) / 5) + 3y = 13

Now we have an equation with only one variable, 'y'.

Step 3: Solve for 'y'

Let's simplify and solve this equation for 'y'. First, distribute the 2:

(2 + 6y) / 5 + 3y = 13

To get rid of the fraction, multiply every term in the equation by 5:

2 + 6y + 15y = 65

Combine the 'y' terms:

2 + 21y = 65

Subtract 2 from both sides:

21y = 63

Divide both sides by 21:

y = 3

Awesome! We've found that y = 3, which matches what we found using the elimination method.

Step 4: Substitute 'y' and Solve for 'x'

Now that we know y = 3, we can substitute this value back into either of the original equations or, even easier, into the expression we found for 'x' in Step 1: x = (1 + 3y) / 5.

x = (1 + 3(3)) / 5

x = (1 + 9) / 5

x = 10 / 5

x = 2

Excellent! We've confirmed that x = 2.

Step 5: The Solution

Just like with the elimination method, we've found our solution:

  • x = 2
  • y = 3

Or, as an ordered pair: (2, 3).

In summary, the substitution method involves isolating one variable and substituting its expression into the other equation. It's a particularly useful technique when one of the equations is already solved for one variable or can be easily solved.

Visualizing the Solution: Graphing the Equations

Okay, guys, we've solved our system of equations algebraically using both elimination and substitution. But what does this solution mean geometrically? Let's put on our graphing hats and visualize what's going on.

Each of our equations, 2x + 3y = 13 and 5x - 3y = 1, represents a straight line on the coordinate plane. The solution to the system of equations, (2, 3), is the point where these two lines intersect. Think about that for a moment – the intersection point is the only point that lies on both lines, meaning it's the only point that satisfies both equations simultaneously.

Step 1: Rewrite the Equations in Slope-Intercept Form

To graph the lines, it's helpful to rewrite the equations in slope-intercept form (y = mx + b), where 'm' is the slope and 'b' is the y-intercept.

Let's start with 2x + 3y = 13:

Subtract 2x from both sides:

3y = -2x + 13

Divide both sides by 3:

y = (-2/3)x + 13/3

So, the slope of the first line is -2/3, and the y-intercept is 13/3 (which is approximately 4.33).

Now, let's rewrite 5x - 3y = 1:

Subtract 5x from both sides:

-3y = -5x + 1

Divide both sides by -3:

y = (5/3)x - 1/3

So, the slope of the second line is 5/3, and the y-intercept is -1/3 (which is approximately -0.33).

Step 2: Plot the Lines

Now we can plot these lines on a graph. You can do this by hand on graph paper or use a graphing calculator or online tool. Here's a quick recap of how to graph a line in slope-intercept form:

  1. Plot the y-intercept (the point where the line crosses the y-axis).
  2. Use the slope (rise over run) to find another point on the line. For example, if the slope is -2/3, you can go down 2 units and right 3 units from the y-intercept to find another point.
  3. Draw a straight line through the two points.

If you plot both lines, you'll see that they intersect at the point (2, 3).

Step 3: Interpret the Graph

The point of intersection, (2, 3), is the visual representation of the solution we found algebraically. It's the one and only point that satisfies both equations. The graph provides a powerful way to confirm our algebraic solution and to understand the relationship between the equations.

In summary, graphing the equations allows us to visualize the solution to the system as the point of intersection of the lines. It provides a geometric interpretation that complements the algebraic methods.

Real-World Applications: Where Systems of Equations Shine

Okay, guys, we've mastered the techniques for solving systems of equations, but let's take a step back and appreciate their real-world power. These aren't just abstract mathematical concepts; they're tools that help us solve problems in various fields, from science and engineering to economics and everyday life.

1. Mixture Problems:

Imagine you're a chemist mixing two solutions with different concentrations of a certain chemical. You need to determine how much of each solution to mix to achieve a desired concentration and volume. This is a classic application of systems of equations. You can set up equations based on the volumes and concentrations of the solutions and then solve for the unknown quantities.

2. Distance, Rate, and Time Problems:

These problems often involve two objects moving at different speeds or in different directions. For example, two trains leaving the same station at different times and traveling at different speeds. You can use systems of equations to determine when and where they will meet or how far apart they will be after a certain time.

3. Supply and Demand in Economics:

The intersection of supply and demand curves determines the equilibrium price and quantity of a product in a market. The supply and demand curves can often be represented by linear equations, forming a system of equations. Solving this system helps economists understand market dynamics and predict prices and quantities.

4. Circuit Analysis in Electrical Engineering:

Electrical circuits can be analyzed using Kirchhoff's laws, which lead to systems of equations. By solving these systems, engineers can determine the currents and voltages in different parts of the circuit, which is crucial for designing and troubleshooting electronic devices.

5. Balancing Chemical Equations in Chemistry:

When balancing chemical equations, you need to find the correct coefficients for each reactant and product to ensure that the number of atoms of each element is the same on both sides of the equation. This often involves setting up and solving a system of equations.

6. Everyday Problems:

Even in everyday situations, systems of equations can be useful. For example, if you're buying a combination of two items with different prices and you have a limited budget, you can use a system of equations to determine how many of each item you can afford.

In summary, systems of equations are a versatile tool for modeling and solving problems in a wide range of fields. Their ability to handle multiple unknowns and constraints makes them an indispensable part of mathematical problem-solving.

Conclusion: Mastering the Art of Solving Systems of Equations

Well, guys, we've reached the end of our journey into the world of systems of equations! We've tackled the problem 2x + 3y = 13 and 5x - 3y = 1 using multiple approaches: the efficient elimination method, the versatile substitution method, and the insightful graphical method. We've seen how these methods not only lead to the same solution but also provide different perspectives on the problem.

We've also explored the real-world applications of systems of equations, demonstrating their power and relevance in various fields. From mixing solutions to analyzing electrical circuits, systems of equations are the unsung heroes behind countless calculations and problem-solving scenarios.

But perhaps the most important takeaway is the process itself. Solving systems of equations isn't just about finding the right numbers; it's about developing critical thinking skills, logical reasoning, and a systematic approach to problem-solving. These are skills that will serve you well in all areas of life.

So, keep practicing, keep exploring, and keep challenging yourselves with new and interesting problems. The world of mathematics is vast and fascinating, and systems of equations are just one small but powerful piece of the puzzle. Keep honing your skills, and who knows what exciting challenges you'll be able to conquer next!